The chemical reaction, 2 O _ 3 3 O _ 2 proceeds as O _ 3 O _ 2 +[ O ] (fast) [ O ]+ O _ 3…
Chemistry · JEE Main · NTA Exams — Chemical Kinetics
The chemical reaction, \(2 \mathrm{O}_{3} \rightarrow 3 \mathrm{O}_{2}\) proceeds as
\(\mathrm{O}_{3} \rightleftharpoons \mathrm{O}_{2}+[\mathrm{O}]\) (fast)
\([\mathrm{O}]+\mathrm{O}_{3} \rightarrow 2 \mathrm{O}_{2}\) (slow)
The rate law expression will be
\(\mathrm{O}_{3} \rightleftharpoons \mathrm{O}_{2}+[\mathrm{O}]\) (fast)
\([\mathrm{O}]+\mathrm{O}_{3} \rightarrow 2 \mathrm{O}_{2}\) (slow)
The rate law expression will be
- Rate = k [O] [O3]
- Rate = k [O3]2 [O2]–1
- Rate = k [O3]2
- Rate = k [O2] [O]
Answer
(B) Rate = k [O 3 ] 2 [O 2 ] –1
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