For the reaction, 2 ~N _ 2 O _ 5 4 NO _ 2 + O _ 2 , the rate equation can be expressed in…
Chemistry · JEE Main · NTA Exams — Chemical Kinetics
For the reaction, \(2 \mathrm{~N}_{2} \mathrm{O}_{5} \rightarrow 4 \mathrm{NO}_{2}+\mathrm{O}_{2},\) the rate equation can be expressed in two ways – \(\frac{\mathrm{d}\left[\mathrm{~N}_{2} \mathrm{O}_{5}\right]}{\mathrm{dt}}\) = k [N2O5] and + \(\frac{\mathrm{d}\left[\mathrm{NO}_{2}\right]}{\mathrm{dt}}\) = k′ [N2 O5] k and k′ are related as:
- 2k = k′
- k = k′
- k = 2k′
- k = 4k′
Answer
(A) 2k = k ′
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