Equation of chord of the circle x 2 + y 2 – 3x – 4y – 4 = 0 which passes through the…
Mathematics · JEE Advanced · NTA Exams — Co-ordinate Geometry
Equation of chord of the circle x2 + y2 – 3x – 4y – 4 = 0 which passes through the origin such that origin divides it in the ratio 4 : 1, is
- x = 0
- 24x + 7y = 0
- 7x + 24y = 0
- 7x – 24y = 0
Answer
(B) 24x + 7y = 0
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