At 5 × 10 5 bar pressure, density of diamond and graphite are 3 g/cc and 2 g/cc…
Chemistry · JEE Advanced · NTA Exams — Chemical Thermodynamics
At 5 × 105 bar pressure, density of diamond and graphite are 3 g/cc and 2 g/cc respectively, at certain temperature ‘T’. Find the value of ∆U–∆H for the conversion of
1 mole of graphite to 1 mole of diamond at temperature
‘T’ :
1 mole of graphite to 1 mole of diamond at temperature
‘T’ :
- 100 kJ/mol
- 50 kJ/mol
- – 100 kJ/mol
- None of these
Answer
(A) 100 kJ/mol
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