The magnifying power of a compound microscope in terms of the magnifying power of…
Physics · JEE Main · NTA Exams — Optics
The magnifying power of a compound microscope in terms of the magnifying power of objective Mo and that of the eyepiece Me is
- \(\frac{M_{o}}{M_{e}}\)
- \(M_{o} \times M_{e}\)
- Mo + Me
- Mo – Me
Answer
(B) M_ o M_ e
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