In Young's double-slit experiment the angular fringe width for the given light is Δθ. Now…
Physics · JEE Main · NTA Exams — Optics
In Young's double-slit experiment the angular fringe width for the given light is Δθ. Now if wavelength of light is doubled while the distance between the slit is halved, the angular fringe width will become
- \(\frac{\Delta \theta}{2}\)
- \(\Delta \theta\)
- \(4 \Delta \theta\)
- \(\frac{\Delta \theta}{4}\)
Answer
(C) 4
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