For the reaction A + 2B → C, the rate of reaction at a given instant can be represented by

Chemistry · JEE Advanced · NTA Exams — Chemical Kinetics

\(+\frac{\mathrm{d}[\mathrm{~A}]}{\mathrm{dt}}=\frac{1}{2} \frac{\mathrm{~d}[\mathrm{~B}]}{\mathrm{dt}}=+\frac{\mathrm{d}[\mathrm{C}]}{\mathrm{dt}}\)
\(\frac{\mathrm{d}[\mathrm{~A}]}{\mathrm{dt}}=+\frac{1}{2} \frac{\mathrm{~d}[\mathrm{~B}]}{\mathrm{dt}}=-\frac{\mathrm{d}[\mathrm{C}]}{\mathrm{dt}}\)
\(-\frac{\mathrm{d}[\mathrm{~A}]}{\mathrm{dt}}=-\frac{1}{2} \frac{\mathrm{~d}[\mathrm{~B}]}{\mathrm{dt}}=+\frac{\mathrm{d}[\mathrm{C}]}{\mathrm{dt}}\)
\(+\frac{\mathrm{d}[\mathrm{~A}]}{\mathrm{dt}}=+\frac{1}{2} \frac{\mathrm{~d}[\mathrm{~B}]}{\mathrm{dt}}=+\frac{\mathrm{d}[\mathrm{C}]}{\mathrm{dt}}\)

Answer

(C) - d [ ~A ] dt =- 1 2 ~d [ ~B ] dt =+ d [ C ] dt

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