In the expansion of ( x + 1 x )^ 15 , if I 1 is the least value of the term independent…
Mathematics · JEE Main · NTA Exams — Binomial Theorem And Its Simple Applications
In the expansion of \(\left(\frac{x}{\cos \theta}+\frac{1}{x \sin \theta}\right)^{15}\), if I1 is the least value of the term independent of x when \(\frac{\pi}{8} \leq \theta \leq \frac{\pi}{4}\) and I2 is the least value of the term independent of x when \(\frac{\pi}{16} \leq \theta \leq \frac{\pi}{8}\), then the ratio I2:I1 is equal to :
- 1: 8
- 1 : 16
- 8 : 1
- 16 : 1
Answer
(A) 1: 8
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