Projection vector of a on b is

Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry

Projection vector of \(\overrightarrow{\mathrm{a}}\)on \(\overrightarrow{\mathrm{b}}\)is

\(\frac{\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{~b}}}{|\overrightarrow{\mathrm{~b}}|^{2}} \overrightarrow{\mathrm{~b}}\)
\(\frac{\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{~b}}}{|\overrightarrow{\mathrm{~b}}|}\)
\(\frac{\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{~b}}}{|\overrightarrow{\mathrm{a}}|}\)
\(\frac{\overrightarrow{\mathrm{a}} \cdot \overrightarrow{\mathrm{~b}}}{|\overrightarrow{\mathrm{a}}|^{2}} \hat{\mathrm{~b}}\)

Answer

(A) a ~b | ~b |^ 2 ~b

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