The rate law for a reaction between the substances A and B is given by rate = [A] n [B] m…
Chemistry · NEET · NTA Exams — Chemical Kinetics
The rate law for a reaction between the substances A and B is given by rate = [A]n [B]m. On doubling the concentration of A and halving the concentration of B, the ratio of the new rate of the earlier rate of the reaction will be as:
- \(\frac{1}{2^{m+1}}\)
- (m + n)
- (n - m)
- 2(n - m)
Answer
(D) 2 (n - m)
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