There exists a function f ( x ) satisfying f (0) = 1, f ′(0) = –1, f ( x ) > 0 for all x…
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
There exists a function f (x) satisfying f (0) = 1, f ′(0) = –1, f (x) > 0 for all x and
- f
- –1 < f
- –2
- f
Answer
(D) f ′ ′ ( x ) x
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