If C is the midpoint of AB and P is any point outside AB, then :
Mathematics · JEE Main · NTA Exams — Vector Algebra
If C is the midpoint of AB and P is any point outside AB, then :
- \(\overrightarrow{\mathrm{PA}}+\overrightarrow{\mathrm{PB}}=\overrightarrow{\mathrm{PC}}\)
- \(\overrightarrow{\mathrm{PA}}+\overrightarrow{\mathrm{PB}}=\overrightarrow{\mathrm{PF}}\)
- \(\overrightarrow{\mathrm{PA}}+\overrightarrow{\mathrm{PB}}+\overrightarrow{\mathrm{PC}}=0\)
- \(\overrightarrow{\mathrm{PA}}+\overrightarrow{\mathrm{PB}}+\overrightarrow{\mathrm{PCL}}=0\)
Answer
(B) PA + PB = PF
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