Thermal decomposition of gaseous X 2 to gaseous X at 298 K takes place according to the…
Chemistry · JEE Advanced · NTA Exams — Equilibrium
Thermal decomposition of gaseous X2 to gaseous X at 298 K takes place according to the following equation :
\(X_{2(g)} \rightleftharpoons 2 X_{(g)}\)
The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.
(Given : R = 0.083 L bar K–1 mol–1)
The incorrect statement among the following, for this reaction, is
\(X_{2(g)} \rightleftharpoons 2 X_{(g)}\)
The standard reaction Gibbs energy, ΔrG°, of this reaction is positive. At the start of the reaction, there is one mole of X2 and no X. As the reaction proceeds, the number of moles of X formed is given by β. Thus, βequilibrium is the number of moles of X formed at equilibrium. The reaction is carried out at a constant total pressure of 2 bar. Consider the gases to behave ideally.
(Given : R = 0.083 L bar K–1 mol–1)
The incorrect statement among the following, for this reaction, is
- decrease in the total pressure will result in formation of more moles of gaseous X
- at the start of the reaction, dissociation of gaseous X2 takes place spontaneously
- bequilibrium = 0.7
- Kc < 1
Answer
(C) b equilibrium = 0.7
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