What is the equilibrium [OH – ] in 0.1413 M H 2 CO 3 ? H _ 2 CO _ 3 + H _ 2 O H _ 3 O ^ +…
Chemistry · JEE Advanced · NTA Exams — Equilibrium
What is the equilibrium [OH–] in 0.1413 M H2CO3 ?
\(\mathrm{H}_{2} \mathrm{CO}_{3}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{H}_{3} \mathrm{O}^{+}+\mathrm{HCO}_{3}^{-}\) (Ka = 4.30 ×10–7)
\(\mathrm{H}_{2} \mathrm{CO}_{3}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{H}_{3} \mathrm{O}^{+}+\mathrm{HCO}_{3}^{-}\) (Ka = 4.30 ×10–7)
- 7.07 × 10–14 M
- 2.46 × 10–4 M
- 4.16 × 10–11 M
- 6.84 × 10–6 M
Answer
(C) 4.16 × 10 –11 M
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