The locus of the centre of a circle, which touches externally the circle x 2 +y 2 –6x –6y…
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The locus of the centre of a circle, which touches externally the circle x2 +y2 –6x –6y +14 =0 and also touches the
y-axis is given by the equation :
y-axis is given by the equation :
- x2 – 6x – 10y + 14 = 0
- x2 – 10x – 6y + 14 = 0
- y2 – 6x – 10y + 14 = 0
- y2 – 10x – 6y + 14 = 0
Answer
(D) y 2 – 10x – 6y + 14 = 0
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