If ax 2 + 2hxy + by 2 = 1, then d ^ 2 y dx ^ 2 is equal to
Mathematics · JEE Advanced · NTA Exams — Limit, Continuity and Differentiability
If ax2 + 2hxy + by2 = 1, then \(\frac{\mathrm{d}^{2} \mathrm{y}}{\mathrm{dx}^{2}}\) is equal to
- \(\frac{a b-h^{2}}{(h x+b y)^{3}}\)
- \(\frac{h^{2}-a b}{(h x+b y)^{3}}\)
- \(\frac{h^{2}+a b}{(h x+b y)^{3}}\)
- None of these
Answer
(B) h^ 2 -a b (h x+b y)^ 3
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