A photon collides with a stationary hydrogen atom in ground state inelastically. Energy…
Chemistry · JEE Advanced · NTA Exams — Atomic Structure
A photon collides with a stationary hydrogen atom in ground state inelastically. Energy of the colliding photon is 10.2 eV. After a time interval of the order of micro second another photon collides with same hydrogen atom inelastically with an energy of 15 eV. What will be observed by the detector?
- One photon of energy 10.2 eV and an electron of energy 1.4 eV
- Two photons of energy 1.4 eV
- Two photons of energy 10.2 eV
- One photon of energy 10.2 eV and another photon of 1.4 eV.
Answer
(D) One photon of energy 10.2 eV and another photon of 1.4 eV.
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