A particle completes 3 revolutions per second on a circular path of radius 8 cm. Find the…

Physics · JEE Main · NTA ExamsRotational Motion

A particle completes 3 revolutions per second on a circular path of radius 8 cm. Find the values of angular velocity and centripetal acceleration of the particle -
  1. 6π \(\frac{\mathrm{rad}}{\mathrm{~s}}\) ; 288π2 \(\frac{\mathrm{cm}}{\mathrm{~s}^{2}}\)
  2. π \(\frac{\mathrm{rad}}{\mathrm{~s}}\); 275π2 \(\frac{\mathrm{cm}}{\mathrm{~s}^{2}}\)
  3. 6π \(\frac{\mathrm{rad}}{\mathrm{~s}}\); 288 \(\frac{\mathrm{cm}}{\mathrm{~s}^{2}}\)
  4. None

Answer

(A) 6 π rad ~s ; 288 π 2 cm ~s ^ 2

Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.

Related practice questions

More Rotational Motion questions · Browse all practice questions