In 2 cos 2 θ + 3sin θ = 0, then the general value of θ is–
Mathematics · JEE Main · NTA Exams — Trigonometry
In 2 cos2 θ + 3sin θ = 0, then the general value of θ is–
- nπ + (−1)n
; n ∈ I - 2n π ± \(\frac{\pi}{6}\); n ∈ I
- nπ + (−1)n+1 \(\frac{\pi}{6}\); n ∈ I
- None of these
Answer
(C) n π + (− 1 ) n+1 6 ; n ∈ I
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