In the given figure, a uniform solid sphere is released on the top of a fixed inclined…

Physics · JEE Advanced · NTA Exams — Rotational Motion

In the given figure, a uniform solid sphere is released on the
top of a fixed inclined plane of inclination 37° and height ‘h’.
It rolls without sliding.

The time taken by the sphere to reach the bottom is

1. \(\sqrt{\frac{2 h}{g}}\)
2. \(\sqrt{\frac{70 h}{9 g}}\)
3. \(\sqrt{\frac{25 h}{18 g}}\)
4. \(\sqrt{\frac{25 h}{6 g}}\)

Answer

(B) 70 h 9 g

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