The maximum possible velocity of the bob at the lowest position of a simple pendulum of…
Physics · JEE Advanced · NTA Exams — Rotational Motion
The maximum possible velocity of the bob at the lowest position of a simple pendulum of length L to oscillate is
- \(\sqrt{5 g L}\)
- \(\sqrt{3 g L}\)
- \(\sqrt{2 g L}\)
- \(\sqrt{g L}\)
Answer
(C) 2 g L
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