On the basis of the following thermochemical data: [ H_ f ^ e (H^ + a q )=0 ] H _ 2 O ( l…
Chemistry · NEET · NTA Exams — Chemical Thermodynamics
On the basis of the following thermochemical data: \(\left[\Delta H_{f}^{e}\left(H^{+} a q\right)=0\right]\)
\(\mathrm{H}_{2} \mathrm{O}(\mathrm{l}) \rightarrow \mathrm{H}^{+}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq})\); ΔH = 57.32 kJ
\(\mathrm{H}_{2}(\mathrm{~g})+\frac{1}{2} \mathrm{O}_{2}(\mathrm{~g}) \rightarrow \mathrm{H}_{2} \mathrm{O}(\mathrm{l})\) ΔH = - 286.02 kJ
The value of enthalpy of formation of OH- ion at 25oC is:
- -22.88 kJ
- -228.88 kJ
- +228.88 kJ
- -343.52 kJ
Answer
(B) -228.88 kJ
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