For the reaction: X _ 2 O _ 4 (I) 2 XO _ 2 ( ~g ) U =2.1 k cal , 5=20 cal ~K ^ -1 at 300…
Chemistry · NEET · NTA Exams — Chemical Thermodynamics
For the reaction:
\(\mathrm{X}_{2} \mathrm{O}_{4}(I) \longrightarrow 2 \mathrm{XO}_{2}(\mathrm{~g})\)
\(\Delta \mathrm{U}=2.1 \mathrm{k} \mathrm{cal}, \Delta 5=20 \mathrm{cal} \mathrm{~K}^{-1} \text { at } 300 \mathrm{~K}\)
Hence, ΔG is:
- 2.7 k cal
- -2.7 k cal
- 9.3 k cal
- -9.3 k cal
Answer
(D) -9.3 k cal
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