AB is a vertical pole with B at the ground level and A at the top. A man finds that the…
Mathematics · JEE Main · NTA Exams — Trigonometry
AB is a vertical pole with B at the ground level and A at the top. A man finds that the angle of elevation of the point A from a certain point C on the ground is 60°. He moves away from the pole along the line BC to a point D such that
CD = 7 m. From D the angle of elevation of the point A is 45°. Then the height of the pole is
CD = 7 m. From D the angle of elevation of the point A is 45°. Then the height of the pole is
- \(\frac{7 \sqrt{3}}{2}\left(\frac{1}{\sqrt{3}+1}\right) \mathrm{m}\)
- \(\frac{7 \sqrt{3}}{2}\left(\frac{1}{\sqrt{3}-1}\right) \mathrm{m}\)
- \(\frac{7 \sqrt{3}}{2}(\sqrt{3}+1) \mathrm{m}\)
- \(\frac{7 \sqrt{3}}{2}(\sqrt{3}-1) \mathrm{m}\)
Answer
(C) 7 3 2 ( 3 +1) m
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