Two moles of an ideal gas at 2 bar and 27 ° C expand isothermally against a constant…
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
Two moles of an ideal gas at 2 bar and 27°C expand isothermally against a constant pressure of 1 bar. The work done by the gas is equal to:
- 3.45 kJ
- 2.5 kJ
- 1.5 kJ
- 4.5 kJ
Answer
(A) 3.45 kJ
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- In a given process of an ideal gas, dw = 0 and dq < 0. Then, for the gas:
- The enthalpies of formation of N 2 O and NO at 298 K are 82 and 90 kJ mol –1 . The enthalpy of the reaction …
- A system absorb 10 kJ of heat at constant volume and its temperature rises from 27°C to 37°C. The value of ∆U…
- A tightly closed thermoflask contains some ice cubes. This constitutes
- Vapour pressure and temperature relationship is shown as, log P= -500[K] T +15 . Heat of vaporisation will be:
- The enthalpies of combustion of carbon and carbon monoxide are - 393.5 and - 283 kJ mol -1 respectively. The…
- Heat cannot flow by itself from a body at lower temperature to a body at higher temperature a statement of…
- What should be the H _ f ^ a of OH ^ - ion, if the standard enthalpy of formation of liquid water is -68.31…
More Chemical Thermodynamics questions · Browse all practice questions