Vapour pressure and temperature relationship is shown as, log P= -500[K] T +15 . Heat of…

Chemistry · JEE Main · NTA ExamsChemical Thermodynamics

Vapour pressure and temperature relationship is shown as, log \(P=\frac{-500[K]}{T}+15 .\) Heat of vaporisation will be:
  1. 2.303 kcal
  2. 4.606 kcal
  3. 500 kcal
  4. 500 cal

Answer

(A) 2.303 kcal

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