Vapour pressure and temperature relationship is shown as, log P= -500[K] T +15 . Heat of…
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
Vapour pressure and temperature relationship is shown as, log \(P=\frac{-500[K]}{T}+15 .\) Heat of vaporisation will be:
- 2.303 kcal
- 4.606 kcal
- 500 kcal
- 500 cal
Answer
(A) 2.303 kcal
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