For the reaction, 2 H _ 2 O ( ~g ) 2 H _ 2 ( ~g )+ O _ 2 ( ~g ) ∆H = 571.6 KJ _ f H ^ of…
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
For the reaction,
\(2 \mathrm{H}_{2} \mathrm{O}(\mathrm{~g}) \longrightarrow 2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g})\) ∆H = 571.6 KJ
\(\Delta_{\mathrm{f}} \mathrm{H}^{\theta}\) of water is :
\(2 \mathrm{H}_{2} \mathrm{O}(\mathrm{~g}) \longrightarrow 2 \mathrm{H}_{2}(\mathrm{~g})+\mathrm{O}_{2}(\mathrm{~g})\) ∆H = 571.6 KJ
\(\Delta_{\mathrm{f}} \mathrm{H}^{\theta}\) of water is :
- 285.8 kJ
- –285.8 kJ
- 1143.2 kJ
- –1143.2 kJ
Answer
(B) –285.8 kJ
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