The dissociation equilibrium of a gas AB 2 can be represented as: 2AB 2 (g) ⇌ 2AB(g) + B…
Chemistry · NEET · NTA Exams — Equilibrium
The dissociation equilibrium of a gas AB2 can be represented as:
2AB2(g) ⇌ 2AB(g) + B2(g)
The degree of dissociation is 'x' and is small compared to 1. The expression relating the degree of dissociation (x) with equilibrium constant Kp and total pressure p is:
- \(\left(\frac{2 K_{p}}{P}\right)\)
- \(\left(\frac{2 K_{p}}{P}\right)^{\frac{1}{3}}\)
- \(\left(\frac{2 K_{p}}{P}\right)^{\frac{1}{2}}\)
- \(\left(\frac{K_{p}}{p}\right)\)
Answer
(B) ( 2 K_ p P )^ 1 3
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