The molar solubility of Cd(OH) 2 is 1.84 10^ -5 M in water. The expected solubility of…
Chemistry · NEET · NTA Exams — Equilibrium
The molar solubility of Cd(OH)2 is \(1.84 \times 10^{-5} \mathrm{M}\) in water. The expected solubility of Cd(OH)2 in a buffer solution of pH = 12 is:
- \(2.49 \times 10^{-14} \mathrm{M}\)
- \(1.84 \times 10^{-3} \mathrm{M}\)
- \(6.23 \times 10^{-11} \mathrm{M}\)
- \(\frac{2.49}{1.84} \times 10^{-9} \mathrm{M}\)
Answer
(C) 6.23 10^ -11 M
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