The velocity v (in cms –1 ) of a particle is given in terms of time t (in sec) by the…
Physics · JEE Main · NTA Exams — Physics and Measurement
The velocity v (in cms–1) of a particle is given in terms of time t (in sec) by the equation.
\(v=a t+\frac{b}{t+c}\) . The dimensions of a, b and c are
\(v=a t+\frac{b}{t+c}\) . The dimensions of a, b and c are
- a
- b
- c
- d
Answer
(C) c
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- Given below are two statements. STATEMENT - 1: Screw gauge with a pitch of 0.5 mm is more accurate than 1 mm…
- [ M ^ a LTA ] is the dimension of
- If a , b , c are vectors such that a + b + c =0 and | a |=7,| b |=5,| c |=3 , then the angle between vector b…
- In the determination of Young’s modulus ( Y = 4 MLg ~d ^ 2 ) by using Searle’s method, a wire of length L = 2…
- Given below are two statements. STATEMENT - 1: All zeros between decimal point and first non-zero digit of a…
- The magnetic force on a moving point charge is F = q ( v B ) . Here, q = electric charge v = velocity of the…
- The simple sum of two co-initial vectors is 16 units. Their vectors sum is 8 units. The resultant of the…
- Subtract 87.9 from 87.963. The answer in corrected significant figures is
More Physics and Measurement questions · Browse all practice questions