A particle moves in a straight line, according to the law x = 4a [t + asin ( t a ) ]…
Physics · JEE Main · NTA Exams — Kinematics
A particle moves in a straight line, according to the law x = 4a [t + asin \(\left(\frac{t}{a}\right)\)], where x is its position in meters, t in sec. & a is some constants, then the velocity is zero at
- x = (4a2 m
- t = sec.
- t = 0 sec.
- none
Answer
(A) x = (4a 2 m
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