How many milliliters (mL) of a 0.0500 M NaOH (a strong base) solution should be added to…
Chemistry · JEE Advanced · NTA Exams — Equilibrium
How many milliliters (mL) of a 0.0500 M NaOH (a strong base) solution should be added to 1.00 L of 0.100 M H3PO4, solution to produce a buffer of pH = 2.00 ? For H3PO4, \(\mathrm{K}_{\mathrm{a}_{1}}\) = 6.67 × 10–3
Given : H3PO4 + OH– (from NaOH) → H2PO4– + H2O
Given : H3PO4 + OH– (from NaOH) → H2PO4– + H2O
- 200
- 400
- 600
- 800
Answer
(D) 800
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- The K sp of Ag 2 CrO 4 is 1.1 x 10 –12 at 298 K. The solubility (in mol/L) of Ag 2 CrO 4 in a 0.1 M AgNO 3…
- Densities of diamond and graphite are 3.5 and 2.3 g/mL respectively. Increase of pressure on the equilibrium…
- A solution which is 10 –3 M each in Mn 2+ , Fe 2+ , Zn 2+ and Hg 2+ is treated with 10 –16 M sulphide ion. If…
- The solubility product constant of AgCN is 2.5×10 –16 . The acid dissociation constant of HCN is 6.2 × 10 –10…
- Solubility of a substance which dissolves with a decrease in volume and absorption of heat will be favoured by
- A solution containing a mixture of 0.05 M NaCl and 0.05 M Nal is taken. (K sp of AgCl = 10 –10 and K sp of…
- The oxidation of SO 2 by O 2 to SO 3 is an exothermic reaction. The yield of SO 3 will be maximum if
- Which among the following salts will give basic solution on hydrolysis ?