The chemical reaction, 2O 3 → 3O 2 proceeds as follows O 3 ⇌ O 2 + O (Fast) O + O 3 → 2O…
Chemistry · JEE Advanced · NTA Exams — Chemical Kinetics
The chemical reaction, 2O3 \(\text { → }\) 3O2 proceeds as follows
O3 \(\text { ⇌ }\) O2 + O (Fast)
O + O3 \(\text { → }\) 2O2 (slow)
The rate law expression should be
O3 \(\text { ⇌ }\) O2 + O (Fast)
O + O3 \(\text { → }\) 2O2 (slow)
The rate law expression should be
- Rate = K [O3]2
- Rate = K[O3]2 [O2]–1
- Rate = K [O3] [O2]
- None
Answer
(B) Rate = K[O 3 ] 2 [O 2 ] –1
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