The standard enthalpy and entropy of vaporization of a liquid are 25 kJ mol -1 and 100 J…
Chemistry · JEE Main · NTA Exams — Chemical Thermodynamics
The standard enthalpy and entropy of vaporization of a liquid are 25 kJ mol-1 and 100 J K-1 mol-1, respectively. The normal boiling point of the liquid is:
- 200 K
- 250 K
- 400 K
- 500 K
Answer
(C) 400 K
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- For a particular process q = –10 kJ and w=25 kJ. Which of the following statements is true?
- The enthalpy of vaporisation of a compound AB at its boiling point (127°C) is 6.4 kJ mol –1 . Its entropy of…
- Which of the following neutralisation reactions is most exothermic ?
- Which of the following reactions represents enthalpy of formation of AgCl ?
- Heat of neutralization of four monobasic acids A, B, C and D are -13.7, -9.4, -11.2 and -12.4 kcal/mol…
- Using the following energy values, determine the lattice energy of KF(s): array ll Property & Energy ( k J ~…
- In a reversible reaction of the type A + B ⇌ AB, in general:
- The enthalpy change for the reaction, C 2 H 6 (g) → 2C(g) + 6H(g) is X kJ. The bond energy of C–H bond is:
More Chemical Thermodynamics questions · Browse all practice questions