The ninth term of the expansion (3 x- 1 2 x )^ is
Mathematics · JEE Main · NTA Exams — Binomial Theorem And Its Simple Applications
The ninth term of the expansion \(\left(3 x-\frac{1}{2 x}\right)^{\prime}\) is
- \(\frac{1}{512 x^{9}}\)
- \(\frac{-1}{512 x^{9}}\)
- \(\frac{-1}{256 \cdot x^{8}}\)
- \(\frac{1}{256 \cdot x^{1}}\)
Answer
(B) -1 512 x^ 9
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