A rocket is launched normal to the surface of the Earth, away from the Sun, along the…
Physics · JEE Advanced · NTA Exams — Gravitation
A rocket is launched normal to the surface of the Earth, away from the Sun, along the line joining the Sun and the Earth. The Sun is 3 × 105 times heavier than the Earth and is at a distance 2.5 × 104 times larger than the radius of the Earth. The escape velocity from Earth’s gravitational field is ve = 11.2 km s–1. The minimum initial velocity (vs) required for the rocket to be able to leave the Sun-Earth system is closest to (Ignore the rotation and revolution of the Earth and the presence of any other planet)
- vs = 62 km s–1
- vs = 22 km s–1
- vs = 72 km s–1
- vs = 42 km s–1
Answer
(D) v s = 42 km s –1
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