A solid sphere of uniform density and radius R applies a gravitational force of…
Physics · JEE Advanced · NTA Exams — Gravitation
A solid sphere of uniform density and radius R applies a gravitational force of attraction equal to F1 on a particle placed at a distance 2R from the centre of the sphere. A spherical cavity of radius R/2 is now made in the sphere as shown in the figure. The sphere with the cavity now applies a gravitational force F2 on the same particle. The ratio F1/F2 is
- \(\frac{1}{2}\)
- \(\frac{3}{4}\)
- \(\frac{7}{8}\)
- \(\frac{9}{7}\)
Answer
(D) 9 7
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