A particle moves in the x-y plane according to the law x = kt and y =kt (1 – at), where k…
Physics · JEE Advanced · NTA Exams — Kinematics
A particle moves in the x-y plane according to the law x = kt and y =kt (1 – at), where k and a are positive constants and t is time. What is the equation of trajectory of the particle?
- y = kx
- \(y=x-\frac{\alpha x^{2}}{k}\)
- \(y=\frac{\alpha x^{2}}{k}\)
- \(y=\alpha x\)
Answer
(B) y=x- x^ 2 k
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- If the displacement of a particle varies with time as x = t + 7, the
- If are non coplanar unit vectors such that then the angle between a ext and b is
- Let two non-collinear unit vectors and form an acute angle. A point P moves so that at any time t the…
- A horizontal wind is blowing with a velocity v towards north-east. A man starts running towards north with…
- A particle is projected vertically upwards with a velocity u from a point O. When it returns to the point of…
- The displacement of a particle after time t is given by x = (k/b2) (1 – e–bt), where b is a constant. What is…
- A drag racing car starts from rest at t = 0 and moves along a straight line with velocity given by v = bt2…
- A projectile is projected at an angle of 15° to the horizontal with some speed v. If another projectile is…