The displacement of a particle after time t is given by x = (k/b2) (1 – e–bt), where b is…
Physics · JEE Advanced · NTA Exams — Kinematics
The displacement of a particle after time t is given by x = (k/b2) (1 – e–bt), where b is a constant. What is the acceleration of the particle?
- ke–bt
- –ke–bt
- \(\frac{k}{b^{2}} e^{-4}\)
- \(\frac{-k}{b^{2}} e^{-k}\)
Answer
(B) –ke–bt
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