An extremum of the function, f(x)= 2-x cos π (x +3) + 1 ^ 2 sin π (x + 3) 0 < x < 4…
Mathematics · JEE Main · NTA Exams — Limit, Continuity and Differentiability
An extremum of the function,
\(f(x)=\frac{2-x}{\pi}\)cos π (x +3) + \(\frac{1}{\pi^{2}}\)sin π (x + 3) 0 < x < 4 occurs at :
\(f(x)=\frac{2-x}{\pi}\)cos π (x +3) + \(\frac{1}{\pi^{2}}\)sin π (x + 3) 0 < x < 4 occurs at :
- x = 1
- x = 2
- x = 3
- x = π
Answer
(B) x = 2, (D) x = π
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