The point on the curve 3 x^ 2 -4 y^ 2 =72 which is nearest to the line 3 x+2 y+1=0 is,
Mathematics · JEE Main · NTA Exams — Co-ordinate Geometry
The point on the curve \(3 x^{2}-4 y^{2}=72\) which is nearest to the line \(3 x+2 y+1=0\) is,
- \((-2,3)\)
- \((-1,3)\)
- \((-6,3)\)
- None of these
Answer
(D) None of these
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