If | a b | = 3 and | a b | = 4, then the angle between a and is
Mathematics · JEE Main · NTA Exams — Three Dimensional Geometry
If \(|\vec{a} \cdot \vec{b}|\) = 3 and \(|\overrightarrow{\mathrm{a}} \times \overrightarrow{\mathrm{b}}|\) = 4, then the angle between
\(\overrightarrow{\mathrm{a}}\) and
is
\(\overrightarrow{\mathrm{a}}\) and
is- cos–1 3/4 or \(\pi-\cos ^{-1} \frac{3}{4}\)
- cos–1 3/5 or \(\pi-\cos ^{-1} \frac{3}{5}\)
- \(\sin ^{-1} \frac{3}{5} \text { or } \pi-\sin ^{-1} \frac{3}{5}\)
- π/4 or \(\frac{3 \pi}{4}\)
Answer
(B) cos –1 3/5 or - ^ -1 3 5
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