If S_ n = 1 2 n - 1 n+1 + 1 2(n+2) then _ n=1 ^ 15 S_ n = 135 k , then the numerical…
Mathematics · JEE Advanced · NTA Exams — Progression and Series
If \(S_{n}=\frac{1}{2 n}-\frac{1}{n+1}+\frac{1}{2(n+2)} \text { then } \sum_{n=1}^{15} S_{n}=\frac{135}{k} \text {, }\)then the numerical quantity k must be
- \(544\)
- \(272\)
- \(1088\)
- \(480\)
Answer
(A) 544
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