For 0 and z= _ n=0 ^ ^ 2 n ^ 2 n , then
Mathematics · JEE Advanced · NTA Exams — Progression and Series
For \(0<\phi<\frac{\pi}{2},\)if \(x=\sum_{n=0}^{\infty} \cos ^{2 n} \phi, y=\sum_{n=0}^{\infty} \sin ^{2 n} \phi\)
and \(z=\sum_{n=0}^{\infty} \cos ^{2 n} \phi \sin ^{2 n} \phi,\)then
and \(z=\sum_{n=0}^{\infty} \cos ^{2 n} \phi \sin ^{2 n} \phi,\)then
- xyz = xz + y
- xyz = xy + z
- xyz = x + y + z
- xyz = yz + x
Answer
(A) xyz = xz + y
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