The mean of a B.D. (binomial distribution) is 9 whose S.D. (standard deviation) is 3 / 2…
Mathematics · JEE Main · NTA Exams — Statistics and Probability
The mean of a B.D. (binomial distribution) is 9 whose S.D. (standard deviation) is 3 / 2 then B.D. is given by
- \(\left(\frac{1}{4}+\frac{1}{2}\right)^{1}\)
- \(\left(\frac{1}{3}+\frac{2}{3}\right)^{12}\)
- \(\left(\frac{1}{4}+\frac{3}{4}\right)^{12}\)
- None of these
Answer
(C) ( 1 4 + 3 4 )^ 12
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