6 ordinary dice are rolled. The probability that at least half of them will show at least…
Mathematics · JEE Main · NTA Exams — Statistics and Probability
6 ordinary dice are rolled. The probability that at least half of them will show at least 3 is
- \(41 \times \frac{2^{4}}{3^{6}}\)
- \(\frac{2^{4}}{3^{6}}\)
- \(20 \times \frac{2^{4}}{3^{6}}\)
- none of these
Answer
(A) 41 2^ 4 3^ 6
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- How many times must a man toss a fair coin so that the probability of having atleast one head is more than…
- A determinant is chosen at random from the set of all determinants of order 2 with elements 0 or 1 only. The…
- Let a, b, c, d and e be the observations with mean m and standard deviation s. The standard deviation of the…
- An unbiased die with faces marked 1, 2, 3, 4, 5 and 6 is rolled four times. Out of four face values obtained…
- A person throws two fair dice. He wins Rs. 15 for throwing a doublet (same numbers on the two dice), wins Rs…
- A coin is tossed 7 times. Each time a man calls head. The probability that he wins the toss on more occasions…
- If the mean deviation of numbers 1_ 1 1+d_ 1 1+2 d_ 1 .1+100 d from their mean is 255, then d is equal to
- A problem in mathematics is given to three student A, B, C and their respective probability of…
More Statistics and Probability questions · Browse all practice questions