A particle starting from rest, moves in a circle of radius 'r'. It attains a velocity of…
Physics · NEET · NTA Exams — Kinematics
A particle starting from rest, moves in a circle of radius 'r'. It attains a velocity of V0 m/s in the nth round. Its angular acceleration will be,
- \(\frac{V_{B}^{2}}{4 \pi n r} \mathrm{rad} / \mathrm{s}^{2}\)
- \(\frac{V_{B}}{n} \mathrm{rad} / \mathrm{s}^{2}\)
- \(\frac{V_{B}^{2}}{2 \pi n r^{2}} \mathrm{rad} / \mathrm{s}^{2}\)
- \(\frac{V_{B}^{2}}{4 \pi n r^{2}} \mathrm{rad} / \mathrm{s}^{2}\)
Answer
(D) V_ B ^ 2 4 n r^ 2 rad / s ^ 2
Sign up free on Edukali to view the step-by-step worked solution and practice thousands of similar questions.
Related practice questions
- A car is moving uniformly at a constant velocity of 40 km/h, then its acceleration is
- A man on an open platform, which is descending at constant speed of 3 ms -1 , throws a ball relative to the…
- Assertion : Two bodies of masses M and m ( M > m ) are allowed to fall from the same height if the air…
- A particle moves with a deceleration proportional to v and the Initial velocity v 0 . Find the time after…
- The wheel of railway carriage is 5 feet in diameter and makes 7 revolutions in a second; how fast is the…
- The Earth cannot be regarded as a true inertial frame of reference because
- A particle has an initial velocity of (3 i +4 j ) and acceleration [0.4 i +0.3 j ] . Its speed after 10 s is
- A body starts from rest and moves with a uniform acceleration. The ratio of the distance covered in the n ^…