A particle starting from rest, moves in a circle of radius 'r'. It attains a velocity of…

Physics · NEET · NTA ExamsKinematics

A particle starting from rest, moves in a circle of radius 'r'. It attains a velocity of V0 m/s in the nth round. Its angular acceleration will be,
  1. \(\frac{V_{B}^{2}}{4 \pi n r} \mathrm{rad} / \mathrm{s}^{2}\)
  2. \(\frac{V_{B}}{n} \mathrm{rad} / \mathrm{s}^{2}\)
  3. \(\frac{V_{B}^{2}}{2 \pi n r^{2}} \mathrm{rad} / \mathrm{s}^{2}\)
  4. \(\frac{V_{B}^{2}}{4 \pi n r^{2}} \mathrm{rad} / \mathrm{s}^{2}\)

Answer

(D) V_ B ^ 2 4 n r^ 2 rad / s ^ 2

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