For any natural number 'm', evaluate (x^ 3 m +x^ 2 m +x^ m ) (2 x^ 2 m +3 x^ m +6 )^ 1 m…
Mathematics · JEE Main · NTA Exams — Integral Calculus
For any natural number 'm', evaluate
\(\int\left(x^{3 m}+x^{2 m}+x^{m}\right)\left(2 x^{2 m}+3 x^{m}+6\right)^{\frac{1}{m}} d x, x>0\).
- \(\frac{1}{6(m+1)}\left\{2 x^{3 m}+3 x^{2 m}+6 x^{m}\right\}^{m+1}+c\)
- \(\frac{1}{6(m+1)}\left(2 x^{3 m}+3 x^{2 m}+6 x^{m}\right)^{\frac{m+1}{m}}+c\)
- \(\frac{1}{2(m+1)}\left\{2 x^{3 m}+3 x^{2 m}+6 x^{m}\right\}^{m-1}+c\)
- None of these
Answer
(B) 1 6(m+1) (2 x^ 3 m +3 x^ 2 m +6 x^ m )^ m+1 m +c
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