The area (in square units) bounded by the curves y= x , 2 y-x+3=0, x-axis and lying in…
Mathematics · JEE Main · NTA Exams — Integral Calculus
The area (in square units) bounded by the curves
\(y=\sqrt{x}, 2 y-x+3=0,\) x-axis and lying in the first quadrant is
\(y=\sqrt{x}, 2 y-x+3=0,\) x-axis and lying in the first quadrant is
- 9
- 6
- 18
- \(\frac{27}{4}\)
Answer
(A) 9
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