Variation of equilibrium constant K for the reaction 2 ~A ( ~s )+ B ( ~g ) C ( ~g )+2 D (…
Chemistry · JEE Advanced · NTA Exams — Equilibrium
Variation of equilibrium constant K for the reaction
\(2 \mathrm{~A}(\mathrm{~s})+\mathrm{B}(\mathrm{~g}) \rightleftharpoons \mathrm{C}(\mathrm{~g})+2 \mathrm{D}(\mathrm{~g})\)
is plotted against absolute temperature T in figure as : ln K vs (1/T)
\(2 \mathrm{~A}(\mathrm{~s})+\mathrm{B}(\mathrm{~g}) \rightleftharpoons \mathrm{C}(\mathrm{~g})+2 \mathrm{D}(\mathrm{~g})\)
is plotted against absolute temperature T in figure as : ln K vs (1/T)
- the forward reaction is exothermic
- the forward reaction is endothermic
- the slope of line is proportional to ∆H
- adding ‘A’ favours forward reaction
Answer
(A) the forward reaction is exothermic, (C) the slope of line is proportional to ∆ H
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